Iron Drawing
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How to draw structure of octahedral complex of iron thiocyanate?
The blood-red color produced by mixing aqueous solutions of Fe(III) and SCN- (and which provides a well-known test of for Fe(III)) is largely due to [Fe(SCN)(H2O)5]2+......[1]
[Fe(H2O)6]3+ + SCN- ⇄ [Fe(SCN)(H2O)5]2+ + H2O
Despite its name octahedral coordination is six coordination so [Fe(SCN)(H2O)5]2+ is the octahedral complex that is asked for.
Go to:
http://en.wikipedia.org/wiki/Coordination_complex
and see how an octahedral complex is drawn e.g., Fe cmplx on immediate right.
Put Fe in the middle with six lines emanating from it (equal length). You make the two bonds coming towards you bold to indicate that they come out of the plane of the paper; and the two others in the plane are dotted to indicate they are behind the paper. Put H2O at end of five of the lines: in 1D: H2O--Fe--OH2; on the sixth site put Fe--SCN (S bound; could bind through N). What beginners don't realize is that all sites in the octahedron are equivalent so you can put the SCN anywhere, but I would put it on the right hand bond that is bold (by convention). Finally, you can put square brackets around the whole drawing or just a small partial bracket in top right corner and put 2+ just outside the bracket. And you're done!
Rant & Drawing Iron man