Linear Shaft
![]() |
| Powered by phpBay Pro |

Help with a difficult question physics?
A pendulum clock has an aluminum pivot shaft having a linear expansion coefficient 24.0 * 10 ^ 6 K-^ -1. At 22 degrees the period of oscillation of the pendulum is 1.00 seconds. If the temperature is reduced to 5 degrees Celsius How long the clock gain or lose in a day?
Use the law: L2 = L1 (1 + α (T2 - T1)) T2 - T1 = - 5 ° C = - 5 K α = 24.0 * 10 ^ 6 ^ -1 K-L2 / L1 = 1 - 05.24.1910 ^ - 6 = 0.99988 frequency of the pendulum is increased by 1 / 0, 99 988 = 1.00012 In one day, will be 24 x ExtraTime 3600 x 0.00012 = 10.368 s
Nippon Pulse S160D Linear Shaft Motor in a Custom Stage
![]() |
![]() 2x SBR20 600mm 900mm 20 MM SUPPORTED LINEAR RAIL SHAFT ROD with 8 SBR20UU US $189.05
|
| Powered by phpBay Pro |


US $870.19



















































































